A parallel plate capacitor is maintained at a certain potential difference. When a 3mm thick slab is introduced between the plates, in order to maintain the same potential difference the distance between the plates is increased by 2.4 mm. Find the dielectric constant of slab.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(5)
Sol. q = q'
C 0 V 0 = CV
C 0 = C as V = V 0 given
C 0 = 
C 1 = 
But by increasing d to d + 0.24 cm then
C 1 becomes C = 
d = d + 0.24 – t + 
K = 
= 5
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Two equal negative charge – q are fixed at the fixed points and on the Y-axis. A positive charge …
An electric line of force in the xy plane is given by equation . A particle with unit positive cha…
A positively charged ball hangs from a silk thread. We put a positive test charge at a point and m…
If on the concentric hollow spheres of radii r and the charge is distributed such that their surf…
Two equal charges of opposite sign separated by a distance constitute an electric dipole of dipol…
A point charge q is placed at a distance a/2 directly above the center of a square of side a. The e…